2x^2-46x+152=0

Solution for 2x^2-46x+152=0 equation:

2x^2-46x+152=0

a = 2; b = -46; c = +152;
Δ = b2-4ac
Δ = -462-4·2·152
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-30}{2*2}=\frac{16}{4}
=4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+30}{2*2}=\frac{76}{4}
=19
$